Wartet auf verifizierte Auflösung: Set Handicap: Oswaldo Alejandro Reyes Tirado (-1.5) vs Jack McGary (+1.5) — Oswaldo Alejandro Reyes Tirado
CoinRithm wartet auf eine vom Anbieter bestätigte Auflösung, bevor dieser Markt als aufgelöst behandelt wird.
Warnung zur DatenqualitätVeraltete Daten
Daten vom 28.10.2026, 00:38 UTC · Richtlinie pm-quality-4
Aktuelle implizite Wahrscheinlichkeit
Set Handicap: Oswaldo Alejandro Reyes Tirado (-1.5) vs Jack McGary (+1.5) — Oswaldo Alejandro Reyes Tirado 100%Führend unter 3 Optionen
Set Handicap: Oswaldo Alejandro Reyes Tirado (-1.5) vs Jack McGary (+1.5) — Oswaldo Alejandro Reyes Tirado 100%Marktqualitat
13 / 100
Niedrige Qualität24h-Volumen
13,8 €
Liquidität
2085,2 €
Niedrige LiquiditätOpen Interest
15,4 $
Kommentare
0
Marktdaten
Aktualisiert vorgestern
Veraltet27. Okt. 26, 01:59 UTC3. Nov. 26, 18:30 UTC
Trends
Set Handicap: Oswaldo Alejandro Reyes Tirado (-1.5) vs Jack McGary (+1.5) — Oswaldo Alejandro Reyes Tirado100%
Jack McGary0%
Set Handicap: Jack McGary (-1.5) vs Oswaldo Alejandro Reyes Tirado (+1.5) — Jack McGaryVerloren
Regeln
This market refers to the tennis match between the named outcome and Oswaldo Alejandro Reyes Tirado in the M15 Mazatlan, Main Draw, originally scheduled for October 27, 2026 at 2:30PM ET.
- This market will resolve to 'the named outcome' if the named outcome advances against Oswaldo Alejandro Reyes Tirado.
- This market will resolve to 'Oswaldo Alejandro Reyes Tirado' if Oswaldo Alejandro Reyes Tirado advances against the named outcome.
- If the match is canceled (not played at all), ends in a tie, or a winner has not been determined by November 10, 2026, 11:59 PM ET (14 days after the scheduled start), this market will resolve to 50-50.
- If the match begins but is not completed, and one player advances due to the opponent's retirement, default, or disqualification, this market will resolve to the player who advances.
- If the match ends in a walkover (player withdraws before the start and the other advances automatically), this market will resolve to 50-50.
