KalshiCerradoComprobar disponibilidadKYC requeridoDatos de resolución verificadosBien calibradoEste mercado se resolvió: Astrid Lew Yan Foon (94%)
Resuelto: 3 nov 2026, 10:08
Resolución verificada por el proveedor
CoinRithm tiene evidencia del ganador y del momento de liquidación respaldada por el proveedor para este mercado.
Resultado Ganador
Astrid Lew Yan Foon
A 7 días
—
A 24 horas
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Aviso de calidad de datosDatos obsoletos
Datos del 3 nov 2026, 9:46 UTC · política pm-quality-4
Cronología de Probabilidad
Ruth Roura Llaverias6%
Astrid Lew Yan Foon94%
Astrid Lew Yan FoonGanada
Ruth Roura LlaveriasPerdida
Reglas
If Astrid Lew Yan Foon wins the Lew Yan Foon vs Roura Llaverias professional tennis match in the 2026 W50 Heraklion Round of 64 after a ball has been played, then the market resolves to Yes.
- The following market refers to the Lew Yan Foon vs Roura Llaverias professional tennis match in the 2026 W50 Heraklion Round of 64 after a ball has been played. If the match does not occur (signaled by a ball being played) due to a player injury, walkover, forfeiture, or any other cancellation (all before the match starts), all markets will resolve to $0.50. If a player withdraws or forfeits after a match has started, that player will resolve to No. If this match is postponed or delayed, the market will remain open and close after the rescheduled match has finished (within two weeks). Kalshi is not affiliated, associated, authorized, endorsed by, or in any way officially connected with the Governing League. All trademarks, logos, and brand names are the property of their respective owners.
Reglas de cada resultado
- Astrid Lew Yan Foon
- If Astrid Lew Yan Foon wins the Lew Yan Foon vs Roura Llaverias professional tennis match in the 2026 W50 Heraklion Round of 64 after a ball has been played, then the market resolves to Yes.
- Ruth Roura Llaverias
- If Ruth Roura Llaverias wins the Lew Yan Foon vs Roura Llaverias professional tennis match in the 2026 W50 Heraklion Round of 64 after a ball has been played, then the market resolves to Yes.
