KalshiFerméVérifier la disponibilitéKYC requisDonnées de résolution vérifiéesBien calibréCe marché s'est résolu: Julian Cash / Lloyd Glasspool (99%)
Résolu: 6 oct. 2026, 09:32
Résolution vérifiée par le fournisseur
CoinRithm dispose d'éléments du fournisseur pour le gagnant et l'heure de règlement de ce marché.
Résultat Gagnant
Julian Cash / Lloyd Glasspool
À 7 jours
—
À 24 heures
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Chronologie des Probabilités
Julian Cash / Lloyd Glasspool99%
Sander Arends / David Pel1%
Julian Cash / Lloyd GlasspoolGagné
Sander Arends / David PelPerdu
Marchés Associés
Questions liées pour le contexte, et non une comparaison de contrats équivalents.
Règles
If Julian Cash / Lloyd Glasspool wins the Arends / Pel vs Cash / Glasspool professional tennis match in the 2026 ATP Beijing Final after a ball has been played, then the market resolves to Yes.
Règlement via:ATP
- The following market refers to the Arends / Pel vs Cash / Glasspool professional tennis match in the 2026 ATP Beijing Final after a ball has been played. If the match does not occur (signaled by a ball being played) due to a player injury, walkover, forfeiture, or any other cancellation (all before the match starts), the market will resolve to a fair price in accordance with the rules. If this match is postponed or delayed, the market will remain open and close after the rescheduled match has finished (within two weeks). Kalshi is not affiliated, associated, authorized, endorsed by, or in any way officially connected with the Governing League. All trademarks, logos, and brand names are the property of their respective owners.
Règles de chaque résultat
- Julian Cash / Lloyd Glasspool
- If Julian Cash / Lloyd Glasspool wins the Arends / Pel vs Cash / Glasspool professional tennis match in the 2026 ATP Beijing Final after a ball has been played, then the market resolves to Yes.
- Sander Arends / David Pel
- If Sander Arends / David Pel wins the Arends / Pel vs Cash / Glasspool professional tennis match in the 2026 ATP Beijing Final after a ball has been played, then the market resolves to Yes.